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PHP Enhancing a Simple PHP Application Paginating a List: Model and View Using a Conditional in a foreach Loop

Paginating a List: Model & View

Q: Right now, this block of code displays all five ice cream flavors that this store carries. Modify it to display only the flavors that are in stock.

''' <?php

$flavors = array(); $flavors[] = array("name" => "Cookie Dough", "in_stock" => true); $flavors[] = array("name" => "Vanilla", "in_stock" => false); $flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false); $flavors[] = array("name" => "Bacon Me Crazy", "in_stock" => true); $flavors[] = array("name" => "Strawberry", "in_stock" => false);

foreach($flavors as $flavor => $value) { if ($flavor=> in_stock = true){ echo $flavor["name"] . "\n"; } }

?> '''

I am not sure what I am missing...

7 Answers

Here's the full code.

<pre><?php

$flavors = array();
$flavors[] = array("name" => "Cookie Dough",      "in_stock" => true);
$flavors[] = array("name" => "Vanilla",           "in_stock" => false);
$flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false);
$flavors[] = array("name" => "Bacon Me Crazy",    "in_stock" => true);
$flavors[] = array("name" => "Strawberry",        "in_stock" => false);

foreach($flavors as $flavor) {

  if($flavor["in_stock"] == true) {
    echo $flavor["name"] . "\n";
  }

}

?></pre>

$flavor["in_stock"] == true goes in the if statement.

its still not working :(

Sorry also change your foreach to foreach($flavors as $flavor)

still no luck :/

Thank you, the only difference was the pre tag and a few formatting changes but I know some of these challenges are picky. :)

make sure to remove your vardump at the end