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Python Python Basics (2015) Number Game App Squared

Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer
Posted by Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer

please can somebody excplain what i do wrong

It has to be checked if the argument is integer or not

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(num=''):

    try:
        if int(num) == num:

            return int(num)**2
        if int(num) != num:
            return num*len(num)
    except Exception:
          pass

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You're trying too hard.

This function won't take so many lines of code. Here's some hints:

  • you should only need to do an int() conversion one time
  • if no exception occurs, you can immediately return the square of the converted number
  • you won't need to compare the number with anything
  • if an exception does occur, return the string expanded by its length (don't "pass")
Oszkár Fehér
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Oszkár Fehér
Treehouse Project Reviewer
Oszkár Fehér
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Oszkár Fehér
Treehouse Project Reviewer

This was the first thing what i was thinking but because it written "If the nr can be converted...or If can't..." i thought for the quiz i have to make it whit "if" statement. thank you