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Python Python Basics (2015) Number Game App Squared

Posted by Andrey Klimushin
Andrey Klimushin
3,614 Points

Pls help to figure out how to defined 'arg' to make my script work

Pls help to figure out how to defined 'arg' to make my script work

squared.py 
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4

def squared(arg):

    while True:
        try:
          arg = int()
          print(arg**2)
          return
        except ValueError:
          print(arg* len(arg))
          return
squared(arg)

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Here's a few hints:

  • just define your function, don't call it yourself (the challenge does that for you)
  • you don't need a loop (because of the return's, it can't loop anyway)
  • you need to pass an argument to int that you want it to convert
  • you need to return the values, not print them

I'll bet you can get it now, but if you're still stuck...     <button' onclick='$("#spoiler").slideDown("slow");$(this).remove()'>Press to Reveal Spoiler</button> <div id='spoiler' style='display:none'>

:warning: SPOILER ALERT

squared.py 
def squared(arg):
    try:
        arg = int(arg)
        return arg ** 2
    except ValueError:
        return arg * len(arg)

</div>

Andrey Klimushin
Andrey Klimushin
3,614 Points
Andrey Klimushin
Andrey Klimushin
3,614 Points

Thanks so much for the explanation! Now I see...