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![Laura Kirby](https://secure.gravatar.com/avatar/d71c31db9bb80b706095a94e43b45a7c?s=96&d=https%3A%2F%2Fecs-static.teamtreehouse.com%2Fassets%2Fcontent%2Fdefault_avatar-445fbbabfc8dc9188fb5967fe43322ee0c3e0dd1e10f378bf8343784af5a13eb.webp&r=pg)
Laura Kirby
2,893 PointsPoorly written prompt. Note to creators and people who get stuck here. `String name = console.readLine();`
The question states, "Create a new variable called name
and accept input from the console using the readLine
method."
In my opinion, obvious solutions here are:
String name = console.readLine();
or
String name;
console.readline();
However, in order for the code to be evaluated as "correct" we must pass a formal argument that prompts the user.
// Actual Solution:
String name = console.readLine("Insert your name: ")
Clearer wording might say, "Create a new variable called name
and assign it to the console input using the readLine
method. Use a formal parameter to prompt the user to enter their name."
angelfirenze
10,870 Pointsangelfirenze
10,870 PointsYou forgot the semicolon at the end.