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33,474 PointsPython Basics Challenge - Continue
I'm having a lot of trouble trying to figure this exercise out - I would appreciate some assistance - Here is my code thus far:
def loopy(items):
# Code goes here
for i in items:
if i(0) == 'a':
continue
print(i)
AND
Here is the exercise I'm working on:
Same idea as the last one. My loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".
I tried indenting continue, and I keep getting this message: "Str object is not callable" - So, I erase the indent, and that still doesn't work - I've also tried several other approaches, but I just don't know what I'm missing...
3 Answers
Steven Parker
231,269 PointsYou're close, but I see a few issues:
- indexing is done with brackets
[]
, not parentheses()
- anything inside a loop must be indented further than the for statement itself
- any conditionally-executed statements must be indented further than the if statement itself
SC3 Rocks
33,474 PointsThank you for your help everyone - It was much appreciated... P :)
Alejandro Byrne
2,562 PointsYour for loop has to be for item in items, not i in items.
Alexander Davison
65,469 PointsActually, the name of the "temporary" variable used in a loop doesn't matter.
It can be whatever your heart desires, as long as it is a Valid Python name.
Just to recap:
- Variables must have only letters, numbers, and underscores _
- Variable names can't start with a number (or Python will think it is a number)
- No special characters other than underscores! (for example, #%^$(*& are all not allowed. Keep in mind this includes spaces!)
- No dashes (- represent a dash)! Python will think you are trying to do subtraction!