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SOLVED!! - Database Foundations SQL Calculating, Aggregating and Other Functions Grouping, Joining and Cleaning Up STEP 3!!

FOR EVERYONE WHO COULDN'T SOLVE THE STEP 3!!

Like before, group by "movie_id" on reviews, select average "score" as "average", filter out averages over 2 and do an outer join on the movies table. Bring back the movie "title" first then the average. Clean up the average and set it to 0 if null.

THE RIGHT ANSWER!!!!

SELECT movies.title, IFNULL(AVG(score),0) AS average FROM reviews RIGHT OUTER JOIN movies ON movies.id = reviews.movie_id GROUP BY reviews.movie_id HAVING average < 2;

John Locke
John Locke
15,479 Points

I'm glad you solved this, Dragan. Some of these MySQL lessons aren't as easy as they look. Keep learning.

2 Answers

Thank you for posting this! I've been stuck on it for hours! I had a full stop instead of a comma in the IFNULL statement! Infuriating but happy now it's solved. Would be an idea for Andrew to speak 'full stop' or 'comma' as he's typing for us newbies, I can't tell the difference on a small macbook air.

Thanks again Dragan.

I'm glad I could help you, Tom! I've been stuck for an hour or two also, but in the end i could make it right. :) I thought if i write here the solution it would help alot of other programmers that they got stuck at that step.

lyonel scapino
lyonel scapino
14,191 Points

this one also worked for me: SELECT title, IFNULL(AVG(score),0) AS average FROM reviews RIGHT OUTER JOIN movies ON reviews.movie_id=movies.id GROUP BY movie_id HAVING average <=2;