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ziriko
680 Pointssome kind of stupid mistake living here
Made the changes must be doing something stupid. The code is from his answer video since I couldn't get mine to work, though now I'm running into the same issues...
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for n in 1...100 {
if (n % 3 == 0) && (n % 5 == 0) {
return "FizzBuzz"
} else if (n % 3 == 0) {
return "Fizz"
} else if (n % 5 == 0) {
return "Buzz"
} else {
return n
}
}
// End code
return "\(n)"
}
2 Answers
Michael Hulet
47,913 PointsPay attention to what the challenge is asking you to do here. Specifically, the challenge says you don't need a default case where the number doesn't match "Fizz", "Buzz", or "FizzBuzz". Currently this part of your solution produces a compiler error for mismatched types. Also, the challenge also says you don't need to loop over anything at all, because the challenge checker handles that for you. All you have to do is determine if something should match "Fizz", "Buzz", or "FizzBuzz" and return the proper word. Other than that, your code looks fine to me
ziriko
680 PointsThank you sir!