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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Paul Carrillo
Paul Carrillo
8,100 Points
Posted by Paul Carrillo
Paul Carrillo
8,100 Points

Storing the returned value

I keep getting an error with my code. I am placing the returnValue in
my variable echo. But its keeps giving me an error. If I delete line two so it can return echo its saying Task 1 is not complete.

script.js 
function returnValue(value) {
  return value ;
  var echo = value + " is good for you";
  return echo;
}

returnValue('pizza');
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
tylerpostuma2
tylerpostuma2
5,175 Points

This is because you are returning something 2 times. 'return' can ONLY be used once in a function, at the very end. Try just returning echo.

Hope this helped!

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher
Jennifer Nordell
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi there, Paul! I think you're doing fairly well but I think you missed part of the instructions. The instructions explicitly say to make the variable echo after your newly created function. But you're making it inside the function. Also the value of echo should contain the result of sending the string into the function. Here's your code reworked a bit:

function returnValue(value) {
  return value;
}

var echo = returnValue('pizza');

We first declare a function that takes a value. We then immediately return a value. It's important to note here that once a return statement is hit in a function, the function exits. This means that the code you wrote would never get to the second return statement.

Now we declare our echo value and set it equal to the result of calling that function and passing in "pizza". The function returns "pizza" and assigns it to echo. If you were to now use console.log("I like " + echo); You'd receive "I like pizza". Hope this helps! :sparkles: