Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Enej Lah
Java Web Development Techdegree Student 957 PointsStuck
I am making a program, but there is someting wrong (3 errors), but I don't know, how to fix it.
Here is the program:
import java.io.Console;
public class Vzem {
public static void main(String[] args) {
int k1 = 0;
int k2 = 0;
int k3 = 0;
public void result() {
if (k1 > 49 || k2 > 49 || k3 > 49) {
console.javac("-----------------------");
}
if (k1 > 49) {
system.out.println("1");
}
if (k2 > 49) {
system.out.println("2");
}
if (k3 > 49) {
system.out.println("3");
}
}
}
}
And here are the errors:
Vzem.java:13: error: illegal start of expression
public void result() {
^
Vzem.java:13: error: illegal start of expression public void result() {
^
Vzem.java:13: error: ';' expected
public void result() {
^
3 errors
Please help.
4 Answers
Alex White
16,750 PointsThat is an error you should be able to solve easily via Google or even better the Java documentation. See here: https://docs.oracle.com/javase/7/docs/api/java/lang/System.html
system is a class not a method which means you have made a common typo. In Java classes begin with a capital letter so it should read:
System.out.println("");
Enej Lah
Java Web Development Techdegree Student 957 PointsThanks.
Lukas Dahlberg
53,736 PointsYou cannot call a non-static method inside public static void main. If you want to use the method result, you need to add the static keyword to it.
Alex White
16,750 PointsYou are creating a method inside another method, which you cannot do. You can have multiple methods in a class and you can call methods from methods but cannot create methods inside methods. refactored:
public class Vzem {
public static void main( String[] args ) {
....
}
public static void result() {
...
}
}
then from inised the 'main' you would call 'result();' or if you wanted result method to not be static as you have written above then you would instantiate the Vzem class inside 'main' and call the method from that:
Vzem vzem = new Vzem();
vzem.result();
Enej Lah
Java Web Development Techdegree Student 957 PointsThank you for solving that problem, but now there is one more thing to fix (I don't know, what is wrong).
Program
import java.io.Console;
public class Vzem {
int k1 = 0;
int k2 = 0;
int k3 = 0;
public void result() {
if (k1 > 49 || k2 > 49 || k3 > 49) {
system.out.println("-----------------------");
}
if (k1 > 49) {
system.out.println("1");
}
if (k2 > 49) {
system.out.println("2");
}
if (k3 > 49) {
system.out.println("3");
}
}
}
Errors:
Someting.java:10: error: package system does not exist
system.out.println("-----------------------");
^
Someting.java:14: error: package system does not exist
system.out.println("1");
^
Someting.java:18: error: package system does not exist
system.out.println("2");
^
Someting.java:22: error: package system does not exist
system.out.println("3");
^
Please help (again).
Enej Lah
Java Web Development Techdegree Student 957 PointsEnej Lah
Java Web Development Techdegree Student 957 Pointsat: public void result() { if (k1 > 49 || k2 > 49 || k3 > 49) { CONSOLE.JAVAC("-----------------------"); } I write console.javac instead of console.printf.