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Yuri Arons
7,281 Pointsstuck again !! :(
this was my try ....... please HELP !
public String getTileCount(){ String count = ""; for(char letter: mHand.toCharArray()){ char display = '-'; if(mHand.indexOf(letter) >= 0 ){ display = letter; } count += display; } return count; }
public class ScrabblePlayer {
private String mHand;
public ScrabblePlayer() {
mHand = "";
}
public String getHand() {
return mHand;
}
public void addTile(char tile) {
// Adds the tile to the hand of the player
mHand += tile;
}
public boolean hasTile(char tile) {
return mHand.indexOf(tile) > -1;
}
public String getTileCount(){
String count = "";
for(char letter: mHand.toCharArray()){
char display = '-';
if(mHand.indexOf(letter) >= 0 ){
display = letter;
}
count += display;
}
return count;
}
}
2 Answers
Steve Hunter
57,712 PointsHi Yuri,
The method needs to take a char as a parameter and return an int. A for:each loop can then be used to iterate through the mHand string and count how many instances of that char occur. So, if the player's hand was H E L L O, the method would be called like: getTileCount('L'); and it would return 2, the number of Ls in the hand.
My solution looks like:
public int getTileCount(char tile){
int count = 0;
for (char letter : mHand.toCharArray()) {
if(letter == tile){
count++;
}
}
return count;
}
I hope that makes sense!
Steve.
Yuri Arons
7,281 Pointsyou saved me ! thanks man !
Steve Hunter
57,712 PointsNo problem! :-)