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james mchugh
6,234 Pointsstuck on this
I've tried every combination I can think of
function returnValue(length) {
return length;
var echo = (returnValue);
returnValue(echo + unit);
}
console.log( echo( 20, 'sq ft') )
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Ben Reynolds
35,170 PointsThe echo variable should be declared after the returnValue function, not inside it. echo's value should be the result of calling returnValue with any string passed in.
Ashley, your code works on your test html page because it's valid javascript, i.e. no syntax errors, it's just not performing the operations in the order the challenge is expecting.
Ashley Elson
Front End Web Development Techdegree Student 5,972 Pointsfunction returnValue(e) {
var echo = e;
return echo;
}
console.log(returnValue('hi'));
This SHOULD work but on the challenge its not saying it works however when I try it on a HTML page it works fine so I'm not entirely sure
Ashley Elson
Front End Web Development Techdegree Student 5,972 PointsAshley Elson
Front End Web Development Techdegree Student 5,972 PointsOO I get it, you're right my bad.
james mchugh
6,234 Pointsjames mchugh
6,234 PointsI'm still confused. I declared the variable echo outside the function, and I tried to return the returnValue, but it's giving me an error message. I'm really confused. I've posted a new one with my last attempt. Thanks for your help Ben, I'm gradually understanding.