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Matt Freeman
3,990 PointsTask 4
this is confusing the hell out of me i change the variable and it still wont let me pass !!! php is really running me down !!!!
2 Answers
Leonardo Hernandez
13,798 PointsTask 4 asks you to change the variable to cookie dough after you have created a conditional checking the value of the variable $flavor.
To display the message "Randy's favorite flavor is cookie dough, also!" , the conditional needs to evaluate to TRUE.
They key here is the equals sign.
If you have one equals sign, Cookie Dough and cookie dough will equal TRUE,
if you have two equals signs, Cookie Dough and cookie dough will equal FALSE.
<?php
$variable = "Cookie dough";
echo "<p>Your favorite flavor of ice cream is ";
echo $variable;
echo ".</p>";
if ($variable = "cookie dough") // Evaluates to TRUE
echo "<p> message </p>";
?>
Paul Franz
4,461 PointsCan you please paste the code you currently have?