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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

idriss Elouilani
PLUS
idriss Elouilani
Courses Plus Student 1,232 Points
Posted by idriss Elouilani
idriss Elouilani
Courses Plus Student 1,232 Points

the 2 task doesn't work

1 function returnValue (drink) { var echo = returnValue (string); return drink; } returnValue (string);

script.js 
function returnValue(drink){
  var echo = returnValue(string);
  return drink;
}
 returnValue(string);
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

4 Answers

Chris Adamson
Chris Adamson
132,143 Points
Chris Adamson
Chris Adamson
132,143 Points

You were pretty close, the echo needs to be declared outside the returnValue function:

function returnValue(drink) {
  return drink;
}

var echo = returnValue("drink");
Austin Flagler
Austin Flagler
10,227 Points
Austin Flagler
Austin Flagler
10,227 Points

The contents of the functions should still just be the line of code returning the drink. Setting the value to the result of calling the function should be outside of the function.

function returnValue(drink){
  return drink;
}
 var echo = returnValue("string");