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838 Pointsthe code I entered looks correct but the when it is submitted it is not accepted
the code is not accepted as answer
// I have initialized a java.io.Console for you. It is in a variable named console.// I have initialized a java.io.Console for you. It is in a variable named console.
String inputFromUser;
String response;
do {
inputFromUser = console.readLine("Do you understand do while loops? ");
}
while(inputFromUser.equalsIgnoreCase("No"));
response = inputFromUser;
console.printf("Because you said " + response + ", you passed the test!");
1 Answer
jb30
44,806 PointsThe challenge is expecting console.printf
to be passed a formatted string, such as console.printf("%s", response)
, instead of using string concatenation.
Steven Parker
231,269 PointsSteven Parker
231,269 PointsYou also don't need the extra variable "inputFromUser". Everything can be done using just "response".