The Conditional Challenge

Hello TeamTreeHouse! I found this challenge particularly challenging. I wrote rewrote and rewrote some more until I essentially gave up. No matter what I did I couldn't get the prompts to prompt. I moved on to the next video to see what the teacher had written for this particular challenge and step by step changed my code to match his looking for my error. Eventually after copying the whole challenge from the video outlining the teachers solution I STILL couldn't get this darned program to run. Please help.

/*

1. Store correct answers
   • When quiz begins, no answers are correct*/ let correctAnswers = 0;

// 2. Store the rank of a player let playerRank = '';

// 3. Select the <main> HTML element const main = document.querySelector('main');

/* 4. Ask at least 5 questions

• Store each answer in a variable
• Keep track of the number of correct answers */ const question1 = prompt('Is this the first question?'); if (question1.toUpperCase() === 'YES') { correctAnswers += 1; } const question2 = prompt('Is this the second question?'); if (question2.toUpperCase() === 'YES') { correctAnswers += 1; } const question3 = prompt('Is this the third question?'); if (question3.toUpperCase() === 'YES') { correctAnswers += 1; } const question4 = prompt('Is this the fourth question?'); if (question4.toUpperCase() === 'YES') { correctAnswers += 1; } const question5 = prompt('Is this the fifth question?'); if (question5.toUpperCase() === 'YES') { correctAnswers += 1; }

/*

1. Rank player based on number of correct answers
   • 5 correct = Gold
   • 3-4 correct = Silver
   • 1-2 correct = Bronze
   • 0 correct = No crown */

if ( correctAnswers === 5 ) { playerRank = "Gold"; } else if (correctAnswers >= 3) { playerRank === "Silver"; } else if (correctAnswers >= 1) { playerRank === "Bronze"; } else (correctAnswers === 0) { playerRank === "Poo"; }

// 6. Output results to the <main> element

main.innerHTML = <h2>You got ${correctAnswers} out of 5 questions correct.</h2> <p>Crown earned: <strong>${rank}</strong></p> ;