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James Khamsan
721 PointsThe following table describes my room temperature preferences. Print the message from the table when a user enters a num
What went wrong?
string input = Console.ReadLine(); int temperature = int.Parse(input);
if(temperature <=21) { Console.WriteLine("Too cold!)"); } else if(temperature <=21 to 22) { Console.WriteLine("Just right."); } else if(tepmerature >=22) { Console.WriteLine("Too hot!"); }
string input = Console.ReadLine();
int temperature = int.Parse(input);
if(temperature <=21)
{
Console.WriteLine("Too cold!)");
}
else if(temperature <=21 to 22)
{
Console.WriteLine("Just right.");
}
else if(tepmerature >=22)
{
Console.WriteLine("Too hot!");
}
1 Answer
Antonio De Rose
20,885 Pointsstring input = Console.ReadLine();
int temperature = int.Parse(input);
if(temperature <=21) // you just have go well aligned with the question should it be less or less than equal
{
Console.WriteLine("Too cold!)");
}
else if(temperature <=21 to 22) //this is how you not combine 2 comparison's
{
Console.WriteLine("Just right.");
}
else if(tepmerature >=22) //should it be greater or greater than equal to
{
Console.WriteLine("Too hot!");
}
Francis Lamy
8,218 PointsFrancis Lamy
8,218 PointsCouple of things I noticed: little things like your <= on if #1, read carefully what the instructions say (less than, not less than equal to)... If #2, it'll never pass, look at your first condition and look at the condition on if #1, also, "to" os not a thing in C# (look for something along the lines of "and" (also not a thing, there are symbols)... If #3, look at your variable name, and, as Antonio said, again look at what the instructions say (greater than... I'm saying this because it'll always say wrong if we let be like that, it's very picky)