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Start your free trialAman Chandolia
2,138 PointsThe Output displays info of only one pet. I have checked my code several times but I can't seem to find any error.
Here's My code
const pets = [
{
name: 'Joey',
type: 'Dog',
breed: 'Australian Shepherd',
age: 8,
photo: 'img/aussie.jpg'
},
{
name: 'Patches',
type: 'Cat',
breed: 'Domestic Shorthair',
age: 1,
photo: 'img/tabby.jpg'
},
{
name: 'Pugsley',
type: 'Dog',
breed: 'Pug',
age: 6,
photo: 'img/pug.jpg'
},
{
name: 'Simba',
type: 'Cat',
breed: 'Persian',
age: 5,
photo: 'img/persian.jpg'
},
{
name: 'Comet',
type: 'Dog',
breed: 'Golden Retriever',
age: 3,
photo: 'img/golden.jpg'
}
];
let html = '';
for (let i = 0; i < Object.keys(pets).length; i++) {
html = `
<h2>${pets[i].name}</h2>
<h3>${pets[i].type} | ${pets[i].breed}</h3>
<p>${pets[i].age}</p>
<img src="${pets[i].photo}" alt="${pets[i].breed}">
`;
}
document.querySelector('main').insertAdjacentHTML('beforeend', html) ;
1 Answer
Steven Parker
231,236 PointsThe assignment operator (=
) replaces the contents of HTML each time in the loop, so when the loop is done it will contain only the values from the last pass. You may have intended to use the concatenating assigment (+=
) instead.
Also, you probably don't want to control the loop with the count of the keys; you likely meant to count the objects themselves (pets.length
).