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C# C# Objects Inheritance Throwing Exceptions

Helmuts Reinis
Helmuts Reinis
1,021 Points

This was't as hard as i thought it would be...

Was prodding around for last 20 minutes ... wondering is did something wrong here, but challenge was passed. Only thing that confuses me is the "throw new Exception();" ... can it be written in any other format under "catch" ?

Program.cs
int value = int.Parse(Console.ReadLine());
try
{
    if (value < 0 || value > 20)
    {
        throw new Exception();
    }

}
catch(Exception)
{
    throw new Exception();
}
Console.WriteLine(string.Format("You entered {0}", value));

2 Answers

Steven Parker
Steven Parker
231,275 Points

:point_right: It looks like you passed, but did it the hard way.

Glad you thought it wasn't so hard! But you really only needed to add the test (if) and the throw inside it.

The try, catch, and the other throw are all not needed and don't actually do anything, since you end up throwing the same exception again anyway.

Helmuts Reinis
Helmuts Reinis
1,021 Points

Awesome... i seem to have overthinked the task. So this should be the simplest way to do it.

if (value < 0 || value > 20) { throw new Exception(); }

Or have a i misunderstood?

pet
pet
10,908 Points

Yes your have understood.