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Davies Oludare
4,900 Pointstry, except returning error: squared didn't return the right answer
Please don't fix it, hints are fine :)
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(a):
try:
return int(a) * a
except ValueError:
return len(a) * a
squared("aaa")
3 Answers
Davies Oludare
4,900 PointsI have fixed it now. Apologies
def squared(a): try: return int(a) * int(a) except ValueError: return a * len(a)
squared("aaa")
andren
28,558 PointsIt's a bit hard to just give a hint since your solution is pretty close. What I'll say is that the challenge expects the return of the function to be an int if a number was provided. Currently your function does not adhere to that expectation.
Edit: Well it seems my response was a bit too late to be helpful, but I'm glad you figured it out on your own. That's one of the best ways to learn when you start out with coding.
Davies Oludare
4,900 Pointsthank you :)
Jennifer Nordell
Treehouse TeacherHi there, Davies! Wow, you're close! So yes, you are just going to get a hint
Inside your try you are trying to convert a to an integer one time... but not both times. It needs to fail if either one of those fail.
Give this another shot with that hint in mind!
edited for additional information
Whoops! Seems like you figured it out while I was busy typing your hint. Kudos on figuring it out yourself!
Davies Oludare
4,900 Pointsthank you :)