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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by Jairo Montenegro
Jairo Montenegro
3,687 Points

What am I doing wrong?

?

script.js 
function returnValue(color) {
 var echo = color;
 return echo;
}

returnValue('My arguement');
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Ryan Ruscett
Ryan Ruscett
23,309 Points
Ryan Ruscett
Ryan Ruscett
23,309 Points

Hey,

Your code (below) - Calls a function that takes a color. Ok that' good. You just need to return the color in the function. There is no need to do var echo = color; and return echo. Just return color (As shown in my code below your code). Then you need to call the function. BUT remember the function returns a value. So you call the function, but you don't store the returned varaible or color into anything. We need to save the returned value from calling the function into var echo. As shown in my code blow you code.

function returnValue(color) {
 var echo = color;
 return echo;
}

returnValue('My arguement');

MY CODE

function returnValue(color) {
  return color

}

var echo = returnValue("My argument")

You may have overthought this which I do all the time. Let me know if this clears it up for you or if you have other questions or issues you would like cleared up.

Thanks!

Jairo Montenegro
Jairo Montenegro
3,687 Points

thanks broski

Dale Bailey
Dale Bailey
20,269 Points
Dale Bailey
Dale Bailey
20,269 Points

A couple of things its asking you put the function into the variable echo and pass it a string of 'my argument' (which is misspelt btw). Like this

function returnValue(color) {
 return color;
}
var echo = returnValue('My argument');
Jairo Montenegro
Jairo Montenegro
3,687 Points

ahh thanks man