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Python Python Basics (2015) Letter Game App Even or Odd Loop

Jonathan Shedd
Jonathan Shedd
1,921 Points
Posted by Jonathan Shedd
Jonathan Shedd
1,921 Points

What is the "return not num % 2" statement supposed to do in this code?

I feel like I've written the code correctly but it keeps saying that there are not enough prints. Also, I'm not entirely sure why the "return not num % 2" statement was added at the end. Any help is greatly appreciated!

even.py 
import random

start = 5

def even_odd(num):
    while start == True:
        num = random.randint(1, 99)
        if num % 2 == 0:
            print("{} is even".format(num))

        else:
            print("{} is odd".format(num))

        start = start - 1
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

2 Answers

Robin *
Robin *
5,670 Points
Robin *
Robin *
5,670 Points

Yep, place while loop under the odd_even function (not in it) then use the func to check if the random number is even if not its odd. Also while start: is that same as while start == True so u can drop that bit. I've written my solution under so if you don't want spoilers don't look :D

import random

start = 5


def even_odd(num):
    return not num % 2

while start:
    num = random.randint(1, 99)
    if even_odd(num):
        print('{} is even'.format(num))
    else:
        print('{} is odd'.format(num))
    start -= 1
Jonathan Shedd
Jonathan Shedd
1,921 Points
Jonathan Shedd
Jonathan Shedd
1,921 Points

Thanks for the help! I was finally able to complete the challenge without looking at the code that you wrote for the challenge. :)

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

:point_right: "return not num % 2" is the body of the even_odd function.

You should not modify this provided function. All of your new code should be outside of this function.

In task 3, you will call this function inside your new loop to check the chosen number.