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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

what th wrong in this function returnValue("car"){ return car; var name="car" } returnValue(car);

i cant pass this qustion

script.js
function returnValue("car"){

  return car;
  var name="car"
}
returnValue(car);
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Hugo Paz
Hugo Paz
15,622 Points

Hi moath,

You dont put parameters in quotes in your function definition, and usually the return is the last line to be executed within a function.

So you can change the code to:

function returnValue(car){

  return car;
}
var car = returnValue("Audi");
//this will set car to Audi

why you dont put this var car = returnValue("Audi"); inside function?

Hugo Paz
Hugo Paz
15,622 Points

If i did that, I would be calling the function inside the function itself which can be useful sometimes but not on this case.

Let's make a change to help you understand what happens better:

function returnValue(car){

  return 'My car is a' + car;
}
var car = returnValue("Audi");
//car will have the following value: "My car is a Audi"

When you run a function that has a return statement, you want to use the result in that return statement to do more operations.