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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Lucas Huerta-Murillo Grau
PLUS
Lucas Huerta-Murillo Grau
Courses Plus Student 1,365 Points
Posted by Lucas Huerta-Murillo Grau
Lucas Huerta-Murillo Grau
Courses Plus Student 1,365 Points

what's wrong here?

...

script.js 
function returnValue( gol ) {
  return gol
}

var echo = returnValue();

returnValue( "GOLAZO" );
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

3 Answers

nico dev
nico dev
20,364 Points
nico dev
nico dev
20,364 Points

Hi Lucas Huerta-Murillo Grau ,

You're following very well all the instructions for the challenge linked to in the top-right of this screen. Good work! And, by the way, that's a cool football-related metaphor, too! :)

Now, I only see two possible problems making it difficult for you to pass the challenge:

  1. I know it's not always strictly necessary, but maybe the lack of the semicolon at the end of your return statement could be giving you trouble.

  2. The one more likely is the fact that the challenge is asking you to pass the argument to the function within the variable declaration (i.e.: not in a separate statement, but at the same time you declare the echo variable).

I hope that helps clarify it enough to you, but otherwise feel free to follow up!

SRIMUGAN J
PLUS
SRIMUGAN J
Courses Plus Student 5,345 Points
SRIMUGAN J
SRIMUGAN J
Courses Plus Student 5,345 Points

Can you Please Elaborate your question here...???

If you are using return, the function stops the execution and return the value in echo, but you didn't pass any arguments in the first call, hence the first call return undefined and again you passed the argument "Golazo" , it will return as Golazo.

If this wasn't your expected answer please ask in detail...

Hope this helps :)

Tommy Leng
seal-mask
.a{fill-rule:evenodd;}techdegree
Tommy Leng
Front End Web Development Techdegree Student 12,417 Points
Tommy Leng
.a{fill-rule:evenodd;}techdegree
Tommy Leng
Front End Web Development Techdegree Student 12,417 Points

function returnValue( gol ) { return gol }

var echo = returnValue('ANY STRING');

You are only storing the 'string' in the variable echo. You don't have to call the function;