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Start your free trialLeo Marco Corpuz
18,975 PointsWhat's wrong with my code?
List isn't showing up. I'm guessing my curly braces are misplaced.
Steven Parker
231,172 PointsCan you make a snapshot of the workspace and provide the link to it?
4 Answers
Thomas Gauperaa
3,584 PointsLooks like you have a curly brace too much at the end of this line? ;
statusHTML+=«<li class=‘out’>»;}}
Steven Parker
231,172 PointsI don't think that's an issue. One brace closes the "else" block and the other one ends the "for" loop block.
In fact, I'd already checked for mismatched braces before I asked for the snapshot.
Thomas Gauperaa
3,584 PointsSteven Parker ah, you're right. Maybe something wrong with the file he's loading?
Steven Parker
231,172 PointsThe snapshot will make a complete analysis possible.
Leo Marco Corpuz
18,975 PointsThanks! I compared my code to the solution and it turned out that I needed an extra closing curling brace to close the response function.
Steven Parker
231,172 PointsBy "response function" do you mean the one assigned to onreadystatechange in the example? The code shown above seems to have properly matching pairs of open and close braces.
Leo Marco Corpuz
18,975 PointsYeah, but I was making changes with the curly braces after I made the post so my code was a little different when I compared it to the solution.
Leo Marco Corpuz
18,975 PointsLeo Marco Corpuz
18,975 PointsHere's my code:
var xhr=new XMLHttpRequest(); xhr.onreadystatechange=function(){ if(xhr.readyState===4){ var employees=JSON.parse(xhr.responseText); var statusHTML="<ul class='bulleted'>"; for(var i=0; i<employees.length; i+=1){ if(employees[i].inoffice===true){ statusHTML+="<li class='in'>"; }else{ statusHTML+="<li class='out'>";} } statusHTML+=employees[i].name; statusHTML+="</li>"; } statusHTML+="</ul>"; document.getElementById('employeeList').innerHTML=statusHTML;
};
xhr.open('GET','../data/employees.json'); xhr.send();