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JavaScript

Posted by Nihad Ahmic
Nihad Ahmic
1,619 Points

When you call noAlert() function for the second time, why the value (5) is not returned again?

Is it something about the RETURN key, that only returns value once. I am confused for seeing the alert box and not seeing the value 5 returned. The case is shown in the end of this video (https://teamtreehouse.com/library/using-multiple-return-statements#questions)

3 Answers

Zimri Leijen
Zimri Leijen
11,835 Points

That's because he is running it in the console and he has a second function right after it alert(), the alert function doens't return anything, therefore you see undefined.

Nihad Ahmic
Nihad Ahmic
1,619 Points

Thank you. But why noAlert() function is not called for the 2nd time. It is well defined. Or it has to do sth with the console?

Zimri Leijen
Zimri Leijen
11,835 Points

it is actually called, as you can see by the alert window popping up. You just don't see the return statement because the console ignores it.

Nihad Ahmic
Nihad Ahmic
1,619 Points
Nihad Ahmic
Nihad Ahmic
1,619 Points

Thanks Zimri Leijen :)

Nikola Lukic
Nikola Lukic
8,061 Points
Nikola Lukic
Nikola Lukic
8,061 Points

Zimri Leijen wrote:

it is actually called, as you can see by the alert window popping up. You just don't see the return statement because the console ignores it.

I don't really understand why the console ignores the return statement from the noAlert() function here. Could someone explain what is happening here or point me in the right direction to learn more about this?