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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Sabaa Talal
Sabaa Talal
Courses Plus Student 733 Points

while loop and random.randint

Hello, this is the task :(Make a while loop that runs until start is falsey. Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99. If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number. Finally, decrement start by 1.) I tried this codes to solve it but it did not work, can you help me figure out what is wrong with it !! sincerely,,

even.py 
import random
start = 5
while True:
    num = random.randint(1,99)    
    def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    print("{}is even".format(num))

else:
    print("{} is odd".format(num))

start = start -1

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Here's a couple of hints:

  • do not modify the provided even_odd function, add your code after it
  • you can use that function for testing your random numbers