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Python Python Basics Functions and Looping Functions

Posted by dakota ferrell
dakota ferrell
2,336 Points

why will the .upper() function not work here

first_name = input ("whats your first name ") print ("hello,", first_name) if first_name == "Dakota": print (first_name, "is learning Python") elif first_name == "billy": print("go away {}!".format(first_name))

else: age = int(input("how old are you? ")) if age <= 6: type = print("Wow youre {}! if your confident with reading already...".format(age)) type = type.upper() print("you should learn python {}!".format(first_name))

print("have a great day {}!".format(first_name))

1 Answer

Maxwell Newberry
Maxwell Newberry
7,693 Points
Maxwell Newberry
Maxwell Newberry
7,693 Points

upper() should be appended to a string, for example:

string_name = "Maxwell Newberry"
string_name.upper()

print(string_name)

Output:

MAXWELL NEWBERRY

In your code, you set type's value as a print statement, not a string.

dakota ferrell
dakota ferrell
2,336 Points

Thanks but it seems like i can only do it like this

else: age = int(input("how old are you? ")) if age <= 6: type = "Wow youre {}! if your confident with reading already...".format(age) type.upper() print (type.upper())

is it because its in a if statement?