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2,819 PointsWorking with the DOM - Help with challenge!
The for loop in app.js cycles over list items and applies a color to each item using the values stored in the colors array. For example, it applies the first color in the array ( #C2272D) to the first list item, the second color (#F8931F) to the second list item, and so on.
Complete the code by setting the variable listItems to refer to an HTMLCollection. The collection should contain all list items in the <ul> element.
// Complete the challenge by writing JavaScript below
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
let listItems;
for ( let i = 0; i < colors.length; i++ ) {
listItems[i].style.color = colors[i];
}
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>JavaScript and the DOM</title>
</head>
<body>
<h1>My List</h1>
<ul>
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="app.js"></script>
</body>
</html>
3 Answers
Steven Parker
231,236 PointsChange the simple declaration of listItems on line 3 to one that also assigns it with the requested HTMLCollection. There are several ways of doing this, but a popular choice is to use the querySelectorAll method.
Sean Poore
5,365 PointsIn app.js you didn't define listItems, you can simply change it to let listItems = document.querySelctor([selector]);
Steven Parker
231,236 PointsThe querySelector (also check the spelling) method only selects one element, but this challenge requires a collection. That's why I suggested using querySelectorAll.
Sean Poore
5,365 PointsIf you were to use querySelector on a class and each item in the collection has said class, doesn't that function the same as querySelectorAll?
Steven Parker
231,236 PointsWhen more than one item matches your selector, querySelector gives you just the first element that matches, but querySelectorAll gives you a collection containing all of them.