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Python Python Basics (2015) Letter Game App Even or Odd Loop

Moses Lagoon
PLUS
Moses Lagoon
Courses Plus Student 660 Points
Posted by Moses Lagoon
Moses Lagoon
Courses Plus Student 660 Points

Wrong no. of prints error. However, logically it makes sense to me. I need help

import random start = 5 def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2 while start != 0: rnum = random.randint(1,99) if even_odd(rnum): print("{} is even".format(rnum)) else: print("{} is odd".format(rnum))

    start = start -1
even.py 
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    while start != 0: 
        rnum = random.randint(1,99)
        if even_odd(rnum):
            print("{} is even".format(rnum))
        else: 
            print("{} is odd".format(rnum))

        start = start -1

2 Answers

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

:point_right: It looks like you put your "while" loop inside the function.

Remember, indentation is critical in Python. Remove the indent from your "while" line to indicate that it is outside the function.

Otherwise, your loop looks good. :+1: