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Python Python Basics (2015) Letter Game App Even or Odd Loop

Chad Dugas
PLUS
Chad Dugas
Courses Plus Student 13,304 Points
Posted by Chad Dugas
Chad Dugas
Courses Plus Student 13,304 Points

Wrong number of prints.

Not sure where I'm going wrong here. I get the error message "Wrong number of prints." Whenever I change the code to try to correct this, it tells me Task 1 is no longer complete. Can anyone see the issue?

even.py 
import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
while start == True:
    rand_num = random.randint(1,99)
    if even_odd(rand_num) == True:
        print("{} is even").format(rand_num)
    else:
        print("{} is odd").format(rand_num)
    start -= 1
Jeff Hartl
seal-mask
.a{fill-rule:evenodd;}techdegree
Jeff Hartl
Python Web Development Techdegree Student 8,420 Points
Jeff Hartl
.a{fill-rule:evenodd;}techdegree
Jeff Hartl
Python Web Development Techdegree Student 8,420 Points

Hi Chad, In both of your print statements, there's a parenthesis in the wrong place. Do you see where?

(I've made the same syntax mistake myself)

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

:point_right: There's a few issues here:

  • the parentheses are not placed correctly in your print statements. See example below :arrow_heading_down:
  • comparing a number to a boolean will invoke type coercion, which will give you the wrong result.
  • you don't need to compare anything against "True". Just naming it is enough to test its "truthiness".
parens.py 
#       print("{} is even").format(rand_num)  <- parenthesis misplaced
        print("{} is even".format(rand_num))  #- fixed