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Python Python Basics (2015) Letter Game App Even or Odd Loop

Kade Carlson
Kade Carlson
5,928 Points

Wrong number of prints?

It says I have the wrong number of prints...I'm also not sure what it's asking me to do when it says "decrement start by 1"

even.py
import random
start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start < 5:
    number = random.randint(1, 99)
    if number % 2 == 0:
        even_odd()
        print("{} is even".format(number))
    else:
        print("{} is odd".format(number))

1 Answer

Steven Parker
Steven Parker
231,269 Points

You loop condition is not correct.

You wrote "while start < 5:", but since start is set to 5 to begin with, this is not true so the loop would never run. Also, you can test something for "falsey" just by naming it, you don't need to compare it to anything.

Then later, you wrote "if number % 2 == 0:", which essentially re-creates the even_odd function. You could just call that function as the if condition and pass it number as the argument.

The line with "even_odd()" by itself doesn't do anything, plus it probably causes a syntax error because it doesn't pass any argument to the function.

And "decrement start by 1" would likely be implemented with this code:

    start -= 1